X^2+3^2=x-3(x-3+16)

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Solution for X^2+3^2=x-3(x-3+16) equation: 



X^2+3^2=X-3(X-3+16)

We move all terms to the left:

X^2+3^2-(X-3(X-3+16))=0

We add all the numbers together, and all the variables

X^2-(X-3(X+13))+3^2=0

We add all the numbers together, and all the variables

X^2-(X-3(X+13))+9=0



We calculate terms in parentheses: -(X-3(X+13)), so:

X-3(X+13)

We multiply parentheses

X-3X-39

We add all the numbers together, and all the variables

-2X-39

Back to the equation:

-(-2X-39)



We get rid of parentheses

X^2+2X+39+9=0

We add all the numbers together, and all the variables

X^2+2X+48=0

a = 1; b = 2; c = +48;
Δ = b2-4ac
Δ = 22-4·1·48
Δ = -188
Delta is less than zero, so there is no solution for the equation

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